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This tutorial will discuss how to write a Swift program to find the sum of all odd numbers upto N.

A number that is not divisible by 2 or we can say that when an odd number is divided by 2 then it leaves some remainder such type of number is known as an odd number. For example, when 2 divides by 2 leave remainder 0 whereas 3 divides by 2 leaves remainder 1. So it means 2 is an even number and 3 is an odd number.

List of odd numbers is −

1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, ……We can calculate the sum of all the odd numbers upto N by adding all the odd numbers present in the given list.

Below is a demonstration of the same −

Input

Suppose our given input is −

Number - 10Output

The desired output would be

1+3+5+7+9 = 25 Sum of odd numbers are 25 AlgorithmFollowing is the algorithm −

Step 1 − Create a function.

Step 2 − Declare a variable to store the sum of the odd numbers upto N – sum = 0.

Step 3 − Run a for loop from 0 to N.

Step 4 − Check if the given number is odd number or not.

if j % 2 != 0Here using % operator, we find the remainder. If the remainder is not equal to 0 then the number is an odd number.

Step 5 − Calculate the sum of odd numbers.

sum += j

Step 6 − Return the sum.

Step 7 − Create a variable named “num” to store the value of N. Here the value of num can be user-defined or pre-defined.

Step 8 − Call the function and pass “num” as a argument in it.

Step 9 − Print the output

Example 1The following program shows how to find the sum of all odd numbers upto N.

import

Glibc

var

sum

=

0

(

“Odd numbers from 0 to (a):”

)

for

j

in

1.

.

.

a

{

if

j

%

2

!=

0

{

sum

+=

j

(

j

,

terminator

:

” ,”

)

}

}

return

sum

}

var

num

=

16

(

“nSum of all the odd numbers from 0 to (num): “

,

sumOddNum

(

a

:

num

)

)

Output Odd numbers from 0 to 16: 1 ,3 ,5 ,7 ,9 ,11 ,13 ,15 , Sum of all the odd numbers from 0 to 16: 64In the above code, we create a function named sumOddNum() function to find the sum of all the odd numbers upto N. This function takes one argument. So the working of the sumOddNum() function is −

sumOddNum

(

16

)

sum

=

0

1st

Iteration

:

for

j

in

0.

..

16

if

0

%

2

!=

0

// false

sum

=

sum

+

j

(

j

,

terminator

:

" ,”) sum = 0 2nd Iteration: for j in 0...16 if 1 % 2 != 0 sum = 0 + 1 = 1 print(j, terminator: "

,”)

// print 1

sum

=

1

3rd

Iteration

:

for

j

in

0.

..

16

if

2

%

2

!=

0

// false

sum

=

sum

+

j

(

j

,

terminator

:

" ,”) sum = 1 4th Iteration: for j in 0...16 if 3 % 2 != 0 sum = 1 + 3 = 4 print(j, terminator: "

,”)

// print 3

sum

=

4

...

so on till

16.

Now we display the sum of all the odd numbers present between 0 to 16 is 64(1+3+5+7+9+11+13+15 = 64).

Example 2The following program shows how to find the sum of all odd numbers upto N.

import

Foundationimport

Glibcvar

sum=

0

(

"Odd numbers from 0 to (a):"

)

for

jin

1.

.

.

a{

if

j%

2

!=

0

{

sum+=

j(

j,

terminator:

" ,"

)

}

}

return

sum}

(

"Please enter the number(N):"

)

var

num=

Int

(

readLine

(

)

!

)

!

(

"nSum of all the odd numbers from 0 to (num): "

,

sumOddNum

(

a:

num)

)

STDIN Input Please enter the number(N): 10 Output Odd numbers from 0 to 10: 1 ,3 ,5 ,7 ,9 , Sum of all the odd numbers from 0 to 10: 25Here the working of the above code is same as the Example 1 the only difference is here we take the value of “num” from the user using readLine() function and convert the input value into integer type using Int() function. So here user enter number 10 so the sum of all the odd numbers present in between 0 to 10 is 25 (1+3+5+7+9= 25)

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## Swift Program To Calculate The Sum Of Rows Of Matrix Elements

A matrix is an arrangement of numbers in rows and columns. Matrix can be of various type like square matrix, horizontal matrix, vertical matrix etc.

In this article, we will learn how to write a swift program to calculate the sum of rows of matrix elements. Here we are using the following methods to find the sum of the rows elements −

Using nested for-in loop

Using in-built function

Method 1: Using nested for-in loopHere we use nested for-in loop to find the sum of rows of matrix elements.

AlgorithmStep 1 − Create a function.

Step 2 − Create a variable named sum to store the sum. The initial value of sum = 0.

Step 3 − Find the number of rows and columns.

Step 4 − Run nested for-in loop to iterate through each row and column.

Step 5 − In this nested loop, add elements row-wise and store the result into sum variable.

Step 6 − After each row reset the value of sum = 0 for the sum of next row elements.

Step 7 − Create a matrix and pass it in the function.

Step 8 − Print the output.

ExampleFollowing Swift program to calculate the sum of rows of matrix elements.

import Foundation import Glibc func rowElementsSum(matrix: [[Int]]) { var sum = 0 let noRow = matrix.count let noColumn = matrix[0].count for R in 0..<noRow { for C in 0..<noColumn { sum += matrix[R][C] } print("Sum of row (R) = (sum)") sum = 0 } } let M = [[1, 2, 2], [1, 1, 6], [7, 8, 3], [2, 4, 2]] print("Matrix is:") for x in 0..<M.count { for y in 0..<M[0].count { print(M[x][y], terminator:" ") } print("n") } rowElementsSum(matrix: M) Output Matrix is: 1 2 2 1 1 6 7 8 3 2 4 2 Sum of row 0 = 5 Sum of row 1 = 8 Sum of row 2 = 18 Sum of row 3 = 8Here in the above code, we have a 4×3 matrix and then pass it in the function named rowElementsSum() to find the sum of the row’s elements of the matrix. In this function, we use nested for loop to iterate through each element of the input matrix and then add it to the corresponding row sum. After finishing the nested for loop this function return the row sums that is row 0 = 5, row 1 = 8, row 2 = 18 and row 3 = 8(according to the input matrix).

Method 2: Using in-built functionTo find the sum of the rows of the given matrix elements we uses reduce(_:_:) function. This function returns a result by combining the elements of the array or any sequence using the given closure.

Syntax func reduce(_initial: Value, _next: Value)Here, initial represent the value to use as an initial accumulating value. It passes to the next for the first time the closure is executed. And next represent a closure that combines an accumulating value and an element of the array into a new accumulating value which if further used for next call of the next closure or return to the caller.

AlgorithmStep 1 − Create a matrix.

Step 2 − Print the matrix.

Step 3 − Create an 1-D array to store the sum of the rows.

Step 4 − Run a for loop to iterate through each row.

Step 5 − Find the sum of the rows elements using reduce() function.

let sum = row.reduce(0, +)Step 6 − Now store the sum of each row in the array using append() function.

RowsSum.append(sum)Step 7 − Print the resultant array.

ExampleFollowing Swift program to calculate the sum of rows of matrix elements.

import Foundation import Glibc let matrix = [[1, 2, 3, 4, 6], [4, 5, 6, 1, 1], [7, 8, 9, 5, 5]] print("Matrix is:") for x in 0..<matrix.count { for y in 0..<matrix[0].count { print(matrix[x][y], terminator:" ") } print("n") } var RowsSum = [Int]() for row in matrix { let sum = row.reduce(0, +) RowsSum.append(sum) } print("So the sums of the individual rows are:", RowsSum) Output Matrix is: 1 2 3 4 6 4 5 6 1 1 7 8 9 5 5 So the sums of the individual rows are: [16, 17, 34]Here in the above code, we have a 5×3 matrix. Then create an empty 1-D array to store the sum of each row. The using for loop we iterate through each row of the given matrix and adds the elements of the row using reduce() function. This sum is then store in the RowsSum array. So according to the given matrix the final result is [16, 17, 34]. Here 16 is the sum of row 0 elements(1+2+3+4+6), 17 is the sum of row 1 elements(4+5+6+1+1) and so on.

ConclusionSo this is how we can calculate the sum of rows of matrix elements. Here using the above methods we can calculate the sum of any type of matrix like 6×6, 9×9, 4×3, 6×7, etc.

## Golang Program To Calculate The Sum Of Columns Of Matrix Elements

A matrix is a collection of numbers arranged in rows and columns, a two-dimensional array, each of the values of this matrix is known as an element. Here we will use three methods to find the sum of column elements and compare each method for the same using go programming.

Here is an example of a matrix and the sum value of it’s columns −

The given matrix is −

0 1 2 4 5 6 8 9 7Sum of elements in column 1 is 12

Sum of elements in column 2 is 15

Sum of elements in column 3 is 15

Algorithm

Step 1 − Import the fmt package.

Step 2 − Now we need to start the main() function.

Step 3 − Then we are creating a matrix naming matrix and assign elements to it.

Step 4 − Print the matrix on the screen using fmt.Println() function.

Step 5 − Initialize a new variable called sum of type int to hold the resultant sum.

Step 6 − To find sum of the column elements use the for loop to iterate over the matrix.

Step 7 − Using the first for loop is used to get the column of the matrix while the second for loop gives us the column of the matrix.

Step 8 − Once the loop gets over the matrix elements update the sum variable by adding values to it.

Step 9 − Print the sum of the matrix on the screen.

Example 1In the following example, we will use a for loop to iterate over the matrix and find the sum of its elements and print it on the screen.

package main import "fmt" func main() { matrix := [][]int{ {0, 1, 2}, {4, 5, 6}, {8, 9, 7}, } fmt.Println("The given matrix is:") for i := 0; i < 3; i++ { for j := 0; j < 3; j++ { fmt.Print(matrix[i][j], "t") } fmt.Println() } fmt.Println() for i := 0; i < len(matrix[0]); i++ { sum := 0 for j := 0; j < len(matrix); j++ { sum += matrix[j][i] } fmt.Printf("Sum of elements in column %d is %dn", i+1, sum) } } Output The given matrix is: 0 1 2 4 5 6 8 9 7 Sum of elements in column 1 is 12 Sum of elements in column 2 is 15 Sum of elements in column 3 is 15 Example 2In this example we will find the sum of the columns of matrix elements using range function.

package main import "fmt" func main() { matrix := [][]int{ {10, 1, 2}, {4, 50, 6}, {8, 9, 7}, } fmt.Println("The given matrix is:") for i := 0; i < 3; i++ { for j := 0; j < 3; j++ { fmt.Print(matrix[i][j], "t") } fmt.Println() } fmt.Println() for i := 0; i < len(matrix[0]); i++ { sum := 0 for _, row := range matrix { sum += row[i] } fmt.Printf("Sum of elements in column %d is %dn", i+1, sum) } } Output The given matrix is: 10 1 2 4 50 6 8 9 7 Sum of elements in column 1 is 22 Sum of elements in column 2 is 60 Sum of elements in column 3 is 15 Example 3In this example we will use the recursion approach to find the sum of columns of matrix elements.

package main import "fmt" func colSum(matrix [][]int, col int) int { if col == len(matrix[0]) { return 0 } sum := 0 for i := range matrix { sum += matrix[i][col] } return sum } func main() { matrix := [][]int{ {20, 1, 22}, {43, 5, 16}, {86, 91, 10}, } fmt.Println("The given matrix is:") for i := 0; i < 3; i++ { for j := 0; j < 3; j++ { fmt.Print(matrix[i][j], "t") } fmt.Println() } fmt.Println() for i := 0; i < len(matrix[0]); i++ { fmt.Printf("Sum of elements in column %d is %dn", i+1, colSum(matrix, i)) } } Output The given matrix is: 20 1 22 43 5 16 86 91 10 Sum of elements in column 1 is 149 Sum of elements in column 2 is 97 Sum of elements in column 3 is 48 ConclusionWe have successfully compiled and executed a go language program to calculate the sum of columns of matrix elements along with examples. In the first and second example we have used for loop and range functions respectively in the main() section of the program while in the last example we have used a separate function to implement the logic.

## Java Program To Calculate Length Of Chord Of The Circle

A circle is a round shape two-dimensional diagram which has no corners. Every circle has an origin point and every point on the circle maintains equal distance from the origin. The distance between the origin and a point in a circle is known as Radius of the circle. And similarly, if we draw a line from one edge to another edge of the circle and the origin is held in the middle of it, that line is known as diameter of the circle. Basically, the diameter is double of the length of the radius.

Chord of the circle refers to a line touching from one endpoint of circle to another end point of circle. Or simply we can say a chord refers to the line whose endpoints lie on the circle. A chord divides the circle into two parts.

As per the problem statement we have to find the length of the chord when the radius of circle and angle subtended at centre by the chord is given.

Formula to find length of chord −

Length = 2 * r * sin(a/2)Where, ‘r’ refers to the radius of the circle and ‘a’ refers to the angle subtended at centre by the chord.

So, let’s explore.

To show you some instances − Instance-1 Let say radius (r) of circle is 3. And angle (a) subtended at centre by the chord is 60 Then by using the formula, length of the chord is 5.19. Instance-2 Let say radius (r) of circle is 4. And angle (a) subtended at centre by the chord is 50 Then by using the formula, length of the chord is 6.12. Instance-3 Let say radius (r) of circle is 4. And angle (a) subtended at centre by the chord is 40. Then by using the formula, length of the chord is 5.1. AlgorithmStep-1 − Get the radius of circle and angle at the centre subtended by the chord either by static input or by user input.

Step-2 − Find the length of the chord by using the formula.

Step-3 − Print the result.

Multiple ApproachesWe have provided the solution in different approaches.

By Using Static Input Values.

By Using User Input Values.

Let’s see the program along with its output one by one.

Approach-1: By Using Static Input ValueIn this approach, we initialize the radius and angle value in the program. Then by using the algorithm we can find the length of the chord.

Example public class Main { public static void main(String[] args) { double r = 4; double a = 40; double length = 2 * r * Math.sin(a * (3.14 / 180)); System.out.println("Length of Chord: "+length); } } Output Length of Chord: 5.140131589369607 Approach-2: By Using User Defined Method with Static Input Value.In this approach, we take user input of radius and angle value in the program. Then call a user defined method by passing these values as parameters and inside the method by using the algorithm we can find the length of the chord.

Example public class Main { public static void main(String[] args) { double r = 4; double a = 40; length_of_chord(r, a); } static void length_of_chord(double r, double a) { double length = 2 * r * Math.sin(a * (3.14 / 180)); System.out.println("Length of Chord: "+length); } } Output Length of Chord: 5.140131589369607In this article, we explored how to find the length of the chord when the radius ofcircle and angle subtended by chord to centre is given by using different approaches in Java.

## Swift Program To Print 8 Star Pattern

This tutorial will discuss how to write swift program to 8 star pattern.

Star pattern is a sequence of “*” which is used to develop different patterns or shapes like pyramid, rectangle, cross, etc. These star patterns are generally used to understand or practice the program flow controls, also they are good for logical thinking.

To create a 8 star pattern we can use any of the following methods −

Using nested for loop

Using stride Function

Below is a demonstration of the same −

Input

Suppose our given input is −

Num = 5Output

The desired output would be −

*** * * * * * * *** * * * * * * *** AlgorithmFollowing is the algorithm −

Step 1 − Declare a variable named rows to store the number of columns.

Step 2 − Declare another variable to store rows −

var val = row * 2 - 1Step 3 − Run outer for loop starting from 0 to val. This loop handle the rows.

Step 5 − Print the output.

Method 1 – Using Nested for LoopWe can create a 8 pattern of “*” or any other pattern using nested for loops. Here each for loop handle different tasks such as outermost for loop is used for new rows, etc.

ExampleThe following program shows how to print 8 star pattern using nested for loop.

var row = 10 var val = row * 2 - 1 for x in 1...val{ for y in 1...row{ print(" ", terminator:"") } else{ print("*", terminator:"") } } } else{ for y in 1...row{ print("*", terminator:"") } else{ print(" ", terminator: "") } } } print(" ") } Output ******** * * * * * * * * * * * * * * * * ******** * * * * * * * * * * * * * * * * ******** Method 2 – Using Stride FunctionSwift provide an in-built function named stride(). The stride() function is used to move from one value to another with increment or decrement. Or we can say stride() function return a sequence from the starting value but not include end value and each value in the given sequence is steps by the given amount.

SyntaxFollowing is the syntax −

stride(from:startValue, to: endValue, by:count)Here,

from − Represent the starting value to used for the given sequence.

to − Represent the end value to limit the given sequence

by − Represent the amount to step by with each iteration, here positive value represent upward iteration or increment and negative value represent the downward iteration or decrement.

ExampleThe following program shows how to print 8 star pattern using stride() function.

import Swift import Foundation var row = 9 var k = row * 2 - 1 for i in stride(from:1, to:k+1, by:1){ for j in stride(from:1, to:row+1, by:1){ print(" ", terminator:"") } else{ print("*", terminator:"") } } } else{ for j in stride(from:1, to:row+1, by:1){ print("*", terminator:"") } else{ print(" ", terminator: "") } } } print(" ") } Output ******* * * * * * * * * * * * * * * ******* * * * * * * * * * * * * * * *******## Swift Program To Find The Given Number Is Strong Or Not

A strong number is a special number in which the sum of the factorial of its digit is equal to the number itself. For example −

Number = 345

345! = 3! + 4! + 5! = 6 + 24 + 120 = 150

Here 345 is not a strong number because the sum of the factorial of its digit is not equal to the number itself.

Number = 145

145! = 1! + 4! + 5! = 1 + 24 + 120 = 145

Here 145 is a strong number because the sum of the factorial of its digit is equal to the number itself.

In this article, we will learn how to write a swift program to find the given number is strong or not.

Algorithm

Step 1 − Create a function.

Step 2 − Create a copy of the original number and initialize sum = 0.

Step 3 − Run while to find the last digit of the given number.

Step 4 − Now find the factorial of all the individual digits of the given number.

Step 5 − Add the factorial of the digits and store the result in the sum variable.

Step 6 − Compare the sum and the original number. Return true if the sum and original number are equal. Otherwise, return false.

Step 7 − Create a test variable to store the number and pass it to the function.

Step 8 − Print the output.

ExampleFollowing the Swift program to find whether the given number is strong or not.

import Foundation import Glibc var originalNum = num var sum = 0 let lDigit = originalNum % 10 var factorial = 1 for x in 1...lDigit { factorial *= x } sum += factorial originalNum /= 10 } return sum == num } let myInput = 345 if CheckStrongNumber(num: myInput) { print("YES! (myInput) is a strong number.") } else { print("NO! (myInput) is not a strong number.") } let myInput2 = 145 if CheckStrongNumber(num: myInput2) { print("YES! (myInput2) is a strong number.") } else { print("NO! (myInput2) is not a strong number.") } Output NO! 345 is not a strong number. YES! 145 is a strong number. ConclusionHere in the above code, we have two numbers that are 345 and 145. Now we create a function to check if the given numbers are strong numbers or not. In this function, first, we first make a copy of the original number and initialize the sum to 0. Now we run a while loop to repeatedly extract the last of the number and then perform the factorial of that digit and add the factorial result to the sum. Then the function checks if the given number is equal to the sum of the factorial of the digits. If yes then the function returns true. Otherwise, return false.

So this is how we can check if the given number is a strong number or not.

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